Mr Jweller gave a distinct number of gold coins to each of his seven children. Any four of her children together received more number of gold coins than remaining three children together. Chandu received maximum number of gold coins. What is the least number of gold coins that could have been received by Chandu?
- 18
- 16
- 17
- 15
Since, we need to minimise the number of gold coins received by the child who received the maximum number of gold coins and it is known that each child received distinct number of gold coins, therefore the number of gold coins received by the children have to be consecutive.
Assume that the number of gold coins received by seven children be (n - 3), (n - 2), (n - 1), (n), (n + 1), (n + 2) and (n + 3)
Given that any four of her children together received more number of gold coins than remaining three children together.
So, if (n - 3) + (n - 2) + (n - 1) + n > (n + 1) + (n + 2) + (n + 3), then the condition given above will be always true.
Or, 4n - 6 > 3n + 6. Therefore, n > 12. So min n=13
Therefore, least number of gold coins that could have been received by the child who received maximum number of gold coins is equal to (n + 3) = 16.
Option B: 16
