# At what speed will Santa reach on time?

Santa walks from home to office everday at 7AM.

On Monday he walks at a rate of 95 m/min. But he reaches office 1 min late.

On Tuesday he walks at a rate of 105 m/min. But he reaches office 1 min early.

On Wednesday he walks at a rate of x m/min. And finally reaches on time.

Find the value of x and at what time did Santa reach office on Wednesday.

On Monday he walks at a rate of 95 m/min. But he reaches office 1 min late.

On Tuesday he walks at a rate of 105 m/min. But he reaches office 1 min early.

On Wednesday he walks at a rate of x m/min. And finally reaches on time.

Find the value of x and at what time did Santa reach office on Wednesday.

Answer: x = 99.75 m/min

and total time of his home to office is 20 min, so he reached office at 7:20AM

Explanation:

let the distance be d,

speed be s,

and time be t.

Formula for distance will is d = st.

On Monday

d = 95(t - 1)

d = 95t - 95 ..........eq(1)

on Tuesday

d = 105(t + 1)

d = 105t + 105 ..........eq(2)

Adding equation (1) and (2)

d = 105t + 105

-d = 95t - 95

---------------

0 = 10t - 200

So t = 20 min

Now we will find distance

d = 105(t + 1)

d = 105(21)

d = 1995

Now we will find Speed

d = st

1995 = s * 20

s = 99.75 m/min

and total time of his home to office is 20 min, so he reached office at 7:20AM

Explanation:

let the distance be d,

speed be s,

and time be t.

Formula for distance will is d = st.

On Monday

d = 95(t - 1)

d = 95t - 95 ..........eq(1)

on Tuesday

d = 105(t + 1)

d = 105t + 105 ..........eq(2)

Adding equation (1) and (2)

d = 105t + 105

-d = 95t - 95

---------------

0 = 10t - 200

So t = 20 min

Now we will find distance

d = 105(t + 1)

d = 105(21)

d = 1995

Now we will find Speed

d = st

1995 = s * 20

s = 99.75 m/min