How many integers, greater than 999 but not greater than 4000, can be formed with the digits 0, 1, 2, 3 and 4, if repetition of digits is allowed?
- 499
- 500
- 375
- 376
Every number is of 4 digits, starting with 1000.
digits allowed are 0, 1, 2, 3 and 4
Unit digit cannot be 0.
Also repetition is allowed.
Lets calculate
_ _ _ _
for 1st digit we have 3 options i.e. 1, 2, and 3 (as 0 cannot be at thousand place and we will calculate 4000 separately).
3 _ _ _
for 2nd, 3rd and 4th digit we have 5 options.
3 5 5 5 = 375
total numbers are 375 and it says not greater than 4000.
which means we can consider 4000
So, 375 + 1 = 376
Total Integers greater than 999 but not greater than 4000, can be formed with the digits 0, 1, 2, 3 and 4, if repetition of digits is allowed are 376
