How many integers, greater than 999 but not greater than 4000, can be formed with the digits 0, 1, 2, 3 and 4, if repetition of digits is allowed?

- 499
- 500
- 375
- 376

Every number is of 4 digits, starting with 1000.

digits allowed are 0, 1, 2, 3 and 4

Unit digit cannot be 0.

Also repetition is allowed.

Lets calculate

_ _ _ _

for 1st digit we have 3 options i.e. 1, 2, and 3 (as 0 cannot be at thousand place and we will calculate 4000 separately).

__3__ _ _ _

for 2nd, 3rd and 4th digit we have 5 options.

__3__ __5__ __5__ __5__ = 375

total numbers are 375 and it says not greater than 4000.

which means we can consider 4000

So, 375 + 1 = 376

**Total Integers greater than 999 but not greater than 4000, can be formed with the digits 0, 1, 2, 3 and 4, if repetition of digits is allowed are 376**